BERNOULLI PRINCIPLES

So everyone should understand the underlying concept of this principle. So read it carefully and keep patience. This principle is strictly based on the conservation of energy. However, we are talking about the topic of hydrodynamics.
Then which type of energy is involved in it. When Bernoulli was doing his research, he observed that, if any ideal fluid is non-viscous, incompressible, streamlined, and irrotational, then at every cross-section throughout the liquid flow, the sum of pressure energy, kinetic energy, and potential energy at per unit volume is constant. Then he expressed this mathematically as follows: latexpage
P+12ρv2+ρgh=constant
Where P stands for pressure energy, 12ρv2 stands for kinetic energy and ρgh
Stands for potential energy.
Now we are going to see, that how did he come to this relationship, so the derivation is as follows:
DERIVATION BERNOULLI’S EQUATION
Let’s take p1, a1, h1, v1, and p2, a2, h2, v2, be the pressure, area of cross-section, height, and velocity of liquid flow at points A and B, respectively. Then the force acting on the fluid at point A is F1=p1a1
See the diagram below for a more precise understanding.

Then distance travel by the fluid in one second at point A is given as = v1×1=v1
Then work done per second on the fluid at point A is :
W1=p1a1v1
similarly, we can say that work done on second point B is,W2=p2a2v2
Then network done by the pressure is given as pressure energy difference.
W=W1−W2=p1a1v1−p2a2v2
But from the equation of continuity, we know that ,
V=a1v1=a2v2=mρ
So work done can be written as
W=p1mρ−p2mρ
This pressure energy of the fluid is further converted into kinetic energy and potential energy, because due to this pressure difference liquid flow from point A to another point B. From doing this liquid attain different heights i.e. From h1 to h2
It means this pressure energy is further balanced by the sum of the change of kinetic energy and potential energy.
p1mρ−p2mρ=(mgh2–mgh1)+(mv222−mv222)
Cancelling m by taking common on both side we get-
(p1−p2)ρ=(gh2−gh1)+(v222−v212)
Multiplying ρ on RHS we get-
p1−p2=ρgh2−ρgh1+ρv222−ρv212
Taking 1 marked on LHS and 2 marked on RHS , we get-
p1+ρgh1+ρv212=p2+ρgh2+ρv222
So both sides are Equal then we can conclude that-
p+12ρv2+ρgh=constant
This mathematical modeling is done by Bernoulli in 1738.
But if both sides are divided by the ρg, then we get-
pρg+h+v22g=constantρg=new constant
Then, pρg is called pressure head and h is the gravitational head or potential head and
v22g is called velocity head.
This suggests that for an ideal fluid that is flowing in a pipe, then the sum of pressure head, gravitational head, and velocity head is always a constant.
Here a video is given to you for a better understanding.
FLUID IN HORIZONTAL PIPE
If the fluid is flowing in a horizontal pipe, then one element of the Bernoulli principle has been eliminated: its height, because the pipe is lying horizontally to the ground level so height is zero. Then for this type of conditions Bernoulli principle as follows:
p1+12ρv21=p2+12ρv21
So it becomes
p+12ρv2=constant
FLUID AT REST
If fluid are in rest, then it’s velocity is zero, it means in Bernoulli equation, kinetic energy element is zero, in such conditions, this principle is as follows:
p1+ρgh1=p2+ρgh2p1−p2=ρg(h2–h1)
Then, in constant form it is written as:
p+ρgh=constant
This is all about the Bernoulli principle.